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ChemistryHigh Weightage β˜…β˜…β˜…β˜…Class 12

Coordination Compounds

Werner's theory, IUPAC nomenclature, isomerism, crystal field theory, and organometallics β€” a distinct chapter with 3–4 predictable EAPCET questions.

3–4Questions in EAPCET
~3%Paper Weightage
5Key Concepts
4Mistake Traps

Concept Core

Ligands, coordination number, IUPAC naming, isomerism, and bonding theories.

Key Terminology
TermDefinitionExample
Central metal ionTransition metal; Lewis acidFe²⁺, Co³⁺, Pt²⁺
LigandElectron donor; Lewis baseNH₃, Cl⁻, en, EDTA
Coordination numberNumber of bonds from ligands to metal6 in [Co(NH₃)₆]³⁺
Coordination sphereCentral metal + ligands in [ ][Co(NH₃)₆]Cl₃
ChelatePolydentate ligand forms ring with metalen, oxalate, EDTA
Types of Ligands (Denticity)
TypeDonor AtomsExamples
Monodentate1Cl⁻, Br⁻, NH₃, Hβ‚‚O, CN⁻, CO
Bidentate2en (ethylenediamine), ox²⁻, bipyridyl
Polydentate4–6EDTA⁴⁻ (hexadentate)
Ambidentate1 (two possible atoms)SCN⁻ (S or N), NO₂⁻ (N or O)
IUPAC Nomenclature Rules

Order: anionic ligands β†’ neutral ligands β†’ metal (oxidation state)

Ligand prefixes: di, tri, tetra, penta, hexa for simple ligands; bis, tris, tetrakis for complex ligands.

If complex is cationic: name normally. If anionic: add -ate suffix to metal name (e.g., ferrate, cobaltate).

Examples: [Co(NH₃)₆]Cl₃ = hexaamminecobalt(III) chloride

Types of Isomerism

Structural isomers:

β€’ Ionisation: [Co(NH₃)β‚…Br]SOβ‚„ vs [Co(NH₃)β‚…SOβ‚„]Br

β€’ Linkage: [Co(NOβ‚‚)(NH₃)β‚…] vs [Co(ONO)(NH₃)β‚…] (ambidentate ligand)

β€’ Coordination: [Co(NH₃)₆][Cr(CN)₆] vs [Cr(NH₃)₆][Co(CN)₆]

Stereoisomers:

β€’ Geometric (cis-trans): square planar MAβ‚‚Bβ‚‚ and octahedral MAβ‚„Bβ‚‚

β€’ Optical: non-superimposable mirror images β€” common in octahedral with bidentate ligands

Crystal Field Theory (CFT)

Ligands as point charges split d-orbitals:

Octahedral: d orbitals split into tβ‚‚g (lower, 3 orbitals) and eβ‚˜ (higher, 2 orbitals). Crystal Field Splitting Energy = Ξ”o.

Strong field ligands (large Ξ”o): CO > CN⁻ > NO₂⁻ > en > NH₃ > Hβ‚‚O > F⁻ > Cl⁻ > Br⁻ > I⁻ (spectrochemical series)

Strong field β†’ low spin (electrons pair up). Weak field β†’ high spin.

EAN Rule & Metal Carbonyls

Effective Atomic Number (EAN): stable complexes often have 18 electrons around the metal (18-electron rule).

Metal carbonyls: Ni(CO)β‚„ (tetrahedral, Ni⁰), Fe(CO)β‚… (trigonal bipyramidal), Cr(CO)₆ (octahedral). CO is a Ο€-acceptor ligand β€” causes back-bonding.

Fe oxidation state test: In Kβ‚„[Fe(CN)₆]: Fe is +2 (ferrocyanide). In K₃[Fe(CN)₆]: Fe is +3 (ferricyanide).

Formula Vault

IUPAC rules, CFT splitting, and ligand charge facts.

Charge of Complex
n(metal) + Ξ£charge(ligands) = overall
Use to find oxidation state
Crystal Field Splitting
Octahedral: tβ‚‚gΒ³ eβ‚˜β° β†’ tβ‚‚g⁢ eβ‚˜β° etc.
Ξ”o = CFT splitting energy
CFSE (Octahedral)
tβ‚‚g: βˆ’0.4Ξ”o per e⁻; eβ‚˜: +0.6Ξ”o per e⁻
Net stabilisation energy
Spectrochemical Series
CO > CN⁻ > ... > F⁻ > I⁻
Strong field β†’ large Ξ”o β†’ low spin
Common Ligand Charges
Cl⁻,Br⁻,I⁻,OH⁻,CN⁻: βˆ’1
ox²⁻,SO₄²⁻: βˆ’2
NH₃,Hβ‚‚O,CO: 0
Neutral or anionic
Naming Cation First
Cation before anion
Ligands alphabetically
Metal last with (OS)
IUPAC nomenclature order
Hybridisation of Metal
CN=4: spΒ³ or dspΒ²
CN=6: spΒ³dΒ² or dΒ²spΒ³
VBT prediction
Effective Atomic Number
EAN = Z βˆ’ oxidation state + 2Γ—(ligand e⁻)
Stable if EAN = noble gas

Worked Examples

5 problems β€” IUPAC naming, oxidation state, isomerism, CFT, and magnetic properties.

EasyName the complex [Co(NH₃)β‚…Cl]Clβ‚‚β–Ύ
Give the IUPAC name of [Co(NH₃)β‚…Cl]Clβ‚‚.
1
Ligands in coordination sphere: 5 NH₃ (neutral, ammine) + 1 Cl⁻ (chlorido)
2
Charge: x + 5(0) + 1(βˆ’1) = +2 β†’ Co is +3. Wait: the complex ion is [Co(NH₃)β‚…Cl]²⁺ (with 2Cl⁻ outside).
3
Name: pentaamminechloridocobalt(III) chloride
βœ“  Pentaamminechloridocobalt(III) chloride
EasyFind oxidation state of Fe in Kβ‚„[Fe(CN)₆]β–Ύ
Find the oxidation state of Fe in Kβ‚„[Fe(CN)₆].
1
Charge balance: 4(+1) + [Fe + 6(CN⁻)] = 0
2
4 + Fe + 6(βˆ’1) = 0 β†’ Fe βˆ’ 2 = βˆ’4 β†’ Fe = +2
3
Fe is in +2 oxidation state (ferrocyanide)
βœ“  Fe = +2 (potassium hexacyanoferrate(II))
MediumHow many geometric isomers does [Pt(NH₃)β‚‚Clβ‚‚] have?β–Ύ
Find the number of geometric isomers of square planar [Pt(NH₃)β‚‚Clβ‚‚].
1
Square planar MAβ‚‚Bβ‚‚: two geometric isomers possible β€” cis and trans.
2
Cis: both NH₃ on same side. Trans: NH₃ on opposite sides.
3
Cis-platin (cancer drug) is the cis isomer.
βœ“  2 isomers β€” cis-[Pt(NH₃)β‚‚Clβ‚‚] and trans-[Pt(NH₃)β‚‚Clβ‚‚]
EAPCET LevelPredict high-spin or low-spin for [Fe(CN)₆]⁴⁻▾
Predict whether [Fe(CN)₆]⁴⁻ is high-spin or low-spin. Find the number of unpaired electrons.
1
Fe in +2 state: electron configuration [Ar]3d⁢. 6 d electrons to fill.
2
CN⁻ is a strong field ligand (high in spectrochemical series) β†’ large Ξ”o.
3
Low-spin d⁢: all 6 electrons fill tβ‚‚gΒ³ first, then pair up β†’ tβ‚‚g⁢ eβ‚˜β°
4
Paired configuration: tβ‚‚g⁢ = 6 electrons all paired β†’ 0 unpaired electrons. Diamagnetic.
βœ“  Low-spin, 0 unpaired electrons, diamagnetic
Trap QuestionCO is a positively charged ligand since it's neutral β€” False?β–Ύ
A student says: 'CO is neutral as a free molecule, so it has no effect on the charge of the complex.' Evaluate.
1
CO is indeed neutral (charge = 0) as a free ligand β€” the student is correct on this point.
2
The trap is in the next step: students then incorrectly ignore CO when calculating metal oxidation state, which is actually correct here.
3
For Ni(CO)β‚„: charge = 0 (neutral complex). CO = 0 each. So Ni = 0 (zerovalent). Ni⁰, not Ni²⁺.
4
CO is a Ο€-acceptor ligand β€” it accepts electron density from metal d-orbitals. This stabilises low oxidation states of metals.
βœ“  CO is neutral (charge = 0) βœ“ β€” Ni(CO)β‚„ has Ni in 0 oxidation state; CO stabilises low OS via Ο€ backbonding

Mistake DNA

4 coordination chemistry errors that EAPCET distractors exploit.

πŸ”’
Wrong Oxidation State Due to Incorrect Ligand Charge
Students assign wrong charge to common ligands, leading to wrong metal oxidation state.
❌ Wrong
K₃[Fe(CN)₆]: CN = 0 (neutral) βœ— β†’ Fe = βˆ’3 (nonsense)
βœ“ Correct
CN⁻ = βˆ’1 each βœ“ 3(+1) + Fe + 6(βˆ’1) = 0 Fe = +3 βœ“
Memorise ligand charges: Cl⁻, Br⁻, I⁻, OH⁻, CN⁻ = βˆ’1. SO₄²⁻, ox²⁻, CO₃²⁻ = βˆ’2. NH₃, Hβ‚‚O, CO, en = 0.
πŸ”€
IUPAC: Listing Ligands in Wrong Order
IUPAC requires ligands listed alphabetically (ignoring di/tri prefixes).
❌ Wrong
[CoClβ‚‚(en)(NH₃)β‚‚]Cl: en listed after NH₃ (alphabetical ignored) βœ—
βœ“ Correct
Alphabetical: ammine, dichloro, ethylenediamine βœ“ (ignore 'di' prefix for alphabetical order) βœ“
Alphabetical order uses the actual ligand name, not the prefix. 'Diammine' comes after 'chlorido' because you compare 'ammine' vs 'chlorido', ignoring 'di'.
🧲
All Transition Metal Complexes are Paramagnetic
Paramagnetic (unpaired electrons) or diamagnetic depends on ligand field strength and d electron count.
❌ Wrong
[Fe(CN)₆]⁴⁻: d⁢, must have unpaired e⁻ β†’ paramagnetic βœ—
βœ“ Correct
CN⁻ = strong field β†’ low spin βœ“ d⁢ low spin β†’ tβ‚‚g⁢ eβ‚˜β° βœ“ 0 unpaired β†’ diamagnetic βœ“
Strong-field ligands force electron pairing β†’ low spin β†’ fewer/no unpaired e⁻ β†’ possibly diamagnetic. Weak-field ligands β†’ high spin β†’ more unpaired e⁻ β†’ paramagnetic.
πŸ”—
Coordination Number = Number of Ligands (Not Bonds)
Coordination number = number of DONOR ATOMS bonded to the metal, not the number of ligand molecules.
❌ Wrong
[Co(en)₃]³⁺ has 3 ligands: CN = 3 βœ— (en is bidentate!)
βœ“ Correct
en is bidentate (2 N donors) βœ“ 3 en Γ— 2 = 6 donor atoms CN = 6 βœ“
Coordination number counts donor atom bonds. Bidentate ligand en provides 2 bonds each. Three en ligands β†’ 6 donor atoms β†’ CN = 6.

Chapter Intelligence

Coordination compounds requires systematic IUPAC knowledge and CFT β€” practise naming and oxidation states.

EAPCET Weightage (2019–2024)
Oxidation state of metal ion
~8
IUPAC nomenclature
~7
Isomerism (geometric, optical)
~6
Magnetic property (spin state)
~5
Crystal field theory
~4
VBT hybridisation
~3
High-Yield PYQ Patterns
Find OS of metal in complexIUPAC name of given complexGeometric isomers of MAβ‚‚Bβ‚‚High spin vs low spin predictionMagnetic moment from unpaired e⁻Number of ions from complex in solutionCoordination number counting
Exam Strategy
  • Oxidation state: set up equation (sum of all charges = overall charge of complex). Ligand charges: neutral (NH₃, Hβ‚‚O, CO, en=0), anionic (Cl⁻, CN⁻, OH⁻=βˆ’1; SO₄²⁻=βˆ’2).
  • IUPAC naming: ligands alphabetically β†’ metal name β†’ (oxidation state in Roman numerals). If complex anion, add -ate to metal (ironβ†’ferrate, cobaltβ†’cobaltate).
  • Magnetic properties: check if ligand is strong-field (CN⁻, CO, NO₂⁻) or weak-field (Cl⁻, Br⁻, Hβ‚‚O). Strong β†’ low spin β†’ fewer unpaired e⁻.
  • Geometric isomers: square planar MAβ‚‚Bβ‚‚ β†’ cis/trans. Octahedral MAβ‚„Bβ‚‚ β†’ cis/trans. MAβ‚‚Bβ‚‚Cβ‚‚ β†’ more isomers.
  • This chapter connects to Atomic Structure (d-orbital splitting) and Transition Elements (d-block properties).
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