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PhysicsHigh Weightage โ˜…โ˜…โ˜…โ˜…Class 12

Magnetism & Moving Charges

Magnetic force on charges and currents, Biot-Savart law, Ampere's law, and galvanometer โ€” expect 3โ€“4 EAPCET questions each year.

3โ€“4Questions in EAPCET
~3%Paper Weightage
10Core Formulas
4Mistake Traps

Concept Core

Magnetic force, field sources, and moving charge circular motion.

Magnetic Force on Moving Charge (Lorentz Force)

A charge q moving with velocity v in magnetic field B experiences:

F = qv ร— B    |F| = qvB sinฮธ

ฮธ = angle between v and B. F is perpendicular to both v and B (use right-hand rule for positive charge).

Key: Magnetic force does NO work on a moving charge (F โŠฅ v always). It changes direction but not speed.

Circular Motion in Magnetic Field

When v โŠฅ B, the charge moves in a circle:

r = mv/(qB) = momentum/(qB) T = 2ฯ€m/(qB) = 2ฯ€r/v f = qB/(2ฯ€m)

Radius proportional to momentum. Period independent of speed (for non-relativistic). Faster particle โ†’ larger circle.

Force on Current-Carrying Conductor
F = IL ร— B    |F| = BIL sinฮธ

L = length of conductor. ฮธ = angle between current direction and B.

F = 0 when current is parallel to B (ฮธ=0).

F is maximum when current โŠฅ B (ฮธ=90ยฐ).

Biot-Savart Law

Magnetic field due to a small current element:

dB = ฮผโ‚€/4ฯ€ ร— IdL sinฮธ/rยฒ For long straight wire: B = ฮผโ‚€I/(2ฯ€r) For circular loop at centre: B = ฮผโ‚€I/(2R)

ฮผโ‚€ = 4ฯ€ร—10โปโท Tยทm/A (permeability of free space)

Ampere's Circuital Law
โˆฎBยทdL = ฮผโ‚€ I_enclosed

For a long solenoid: B = ฮผโ‚€nI (n = turns per unit length)

For a toroid: B = ฮผโ‚€nI (n = N/2ฯ€r, N = total turns)

Outside a solenoid: B = 0

Moving Coil Galvanometer & Its Conversions

Deflection: ฮธ = NIAB/(k) where k = restoring constant.

To ammeter: add low resistance (shunt) in parallel. S = Igร—G/(Iโˆ’Ig)

To voltmeter: add high resistance in series. R = V/Ig โˆ’ G

Formula Vault

Magnetism formulas โ€” force, field, and instruments.

Lorentz Force
F = qvB sinฮธ
ฮธ = angle v makes with B
Circular Motion Radius
r = mv/(qB)
Proportional to momentum
Cyclotron Period
T = 2ฯ€m/(qB)
Independent of speed
Force on Conductor
F = BIL sinฮธ
L = wire length; ฮธ = angle to B
Straight Wire Field
B = ฮผโ‚€I/(2ฯ€r)
At perpendicular distance r
Circular Loop at Centre
B = ฮผโ‚€I/(2R)
R = radius of loop
Solenoid
B = ฮผโ‚€nI
n = turns per unit length
Torque on Current Loop
ฯ„ = NIAB sinฮธ
N turns; A = area; ฮธ = angle to B
Shunt (Galvanometerโ†’Ammeter)
S = IgG/(Iโˆ’Ig)
Ig = galvanometer full-scale current
Series R (โ†’Voltmeter)
R = V/Ig โˆ’ G
G = galvanometer resistance

Worked Examples

5 problems โ€” Lorentz force, circular motion, wire field, solenoid, galvanometer.

EasyForce on a proton moving at 10โถ m/s in B = 0.5 T (v โŠฅ B)โ–พ
A proton (q = 1.6ร—10โปยนโน C) moves at 10โถ m/s perpendicular to B = 0.5 T. Find the magnetic force.
1
F = qvB sinฮธ = qvB (since ฮธ=90ยฐ, sin90ยฐ=1)
2
F = 1.6ร—10โปยนโน ร— 10โถ ร— 0.5 = 8ร—10โปยนโด N
โœ“  F = 8ร—10โปยนโด N
EasyFind radius of circular path for electron in B=0.01T, v=10โท m/sโ–พ
An electron (m=9.1ร—10โปยณยน kg, q=1.6ร—10โปยนโน C) moves at 10โท m/s perpendicular to B=0.01 T. Find the radius.
1
r = mv/(qB) = (9.1ร—10โปยณยน ร— 10โท)/(1.6ร—10โปยนโน ร— 0.01)
2
= 9.1ร—10โปยฒโด / 1.6ร—10โปยฒยน = 5.69ร—10โปยณ m โ‰ˆ 5.7 mm
โœ“  r = 5.7 mm
MediumField at 10 cm from a long wire carrying 5 Aโ–พ
Find the magnetic field at 10 cm from a long straight wire carrying 5 A. (ฮผโ‚€ = 4ฯ€ร—10โปโท Tยทm/A)
1
B = ฮผโ‚€I/(2ฯ€r) = (4ฯ€ร—10โปโท ร— 5)/(2ฯ€ ร— 0.1)
2
= (4ฯ€ร—10โปโท ร— 5)/(2ฯ€ ร— 0.1) = (20ฯ€ร—10โปโท)/(0.2ฯ€) = 10โปโต T = 10 ฮผT
โœ“  B = 10 ฮผT
EAPCET LevelConvert galvanometer (G=50ฮฉ, Ig=1mA) to ammeter reading 5Aโ–พ
A galvanometer has G=50ฮฉ and full-scale deflection at Ig=1 mA. Find the shunt resistance to make it read 5 A.
1
Shunt S = Ig ร— G / (I โˆ’ Ig) = (1ร—10โปยณ ร— 50) / (5 โˆ’ 1ร—10โปยณ)
2
= 0.05 / 4.999 โ‰ˆ 0.01 ฮฉ = 10 mฮฉ
โœ“  Shunt S โ‰ˆ 0.01 ฮฉ
Trap QuestionMagnetic force does work on a moving charge โ€” True or False?โ–พ
A student claims that since magnetic force deflects a moving charge, it does work on it and speeds it up. Evaluate.
1
The trap: Magnetic force is always perpendicular to velocity (F = qvร—B โ†’ F โŠฅ v).
2
Work = Fยทd = F d cosฮธ. Since ฮธ = 90ยฐ always, cos90ยฐ = 0 โ†’ W = 0.
3
Therefore magnetic force does NO work. The charge's speed remains constant.
4
Only the direction changes (circular motion). A magnetic field cannot speed up or slow down a charge.
โœ“  False โ€” magnetic force is always โŠฅ to velocity, so W = 0; speed is unchanged

Mistake DNA

4 magnetism errors from EAPCET distractor analysis.

โšก
Magnetic Force Does Work: Confusing Direction Change with Speed Change
Magnetic force changes the direction of velocity, not its magnitude. No work is done.
โŒ Wrong
B field deflects charge โ†’ charge speeds up โœ— (work = 0; speed constant)
โœ“ Correct
F โŠฅ v always โœ“ W = Fยทv = 0 โœ“ Only direction changes; speed stays constant โœ“
In circular motion under B: centripetal force (magnetic) is perpendicular to motion. Speed stays constant throughout. Only a tangential force can change speed.
๐Ÿ”„
Right-Hand Rule: Curling Fingers in the Wrong Direction
For current in a straight wire: use right-hand rule โ€” thumb points along current, fingers curl in direction of B field circles.
โŒ Wrong
Current upward: B circles clockwise when viewed from above โœ—
โœ“ Correct
Thumb = current direction โœ“ Fingers curl = B direction โœ“ Current up โ†’ B circles counterclockwise (from above)
Point thumb in direction of current (conventional, +charge direction), curl fingers โ€” they show the direction of circular magnetic field lines around the wire.
๐Ÿ”ข
Radius of Circular Motion: r = qB/mv instead of mv/(qB)
The formula r = mv/(qB) is often inverted. A larger mass/speed gives larger radius, which the correct formula shows.
โŒ Wrong
r = qB/(mv) โœ— โ†’ heavier particle: smaller radius (wrong!)
โœ“ Correct
r = mv/(qB) โœ“ Heavier/faster โ†’ larger r โœ“ Stronger B โ†’ smaller r โœ“
Derive from qvB = mvยฒ/r: cancelling v โ†’ r = mv/(qB). Momentum mv is in numerator, charge q and field B are in denominator.
๐Ÿ“ป
Solenoid: Forgetting B = 0 Outside
A solenoid creates a uniform B inside. Outside the solenoid, the field is negligibly zero (unlike a bar magnet).
โŒ Wrong
Outside a long solenoid: B = ฮผโ‚€nI/2 or similar โœ—
โœ“ Correct
Outside a long solenoid: B โ‰ˆ 0 โœ“ Inside: B = ฮผโ‚€nI โœ“ Field confined inside
A long solenoid is like an ideal magnet โ€” field is uniform inside, nearly zero outside. This is why solenoids are used to create controlled, contained magnetic fields.

Chapter Intelligence

Magnetism connects to Current Electricity and leads to EMI & AC Circuits.

EAPCET Weightage (2019โ€“2024)
Force on charge/conductor in B
~8
Circular motion in magnetic field
~6
Biot-Savart (wire, loop)
~5
Solenoid B = ฮผโ‚€nI
~4
Galvanometer conversions
~3
High-Yield PYQ Patterns
F = qvB sinฮธ force calculationRadius of circular motion in BB at distance from long wireConvert galvanometer to ammeterSolenoid: B = ฮผโ‚€nI numericalTorque on current loop in field
Exam Strategy
  • Direction of force: use F = qvร—B. For positive charge, use right-hand rule: fingers point along v, curl toward B โ€” thumb points along F. For negative charge, reverse.
  • Circular motion in B: r = mv/(qB). Heavier/faster particles trace bigger circles. Period T = 2ฯ€m/(qB) is independent of speed โ€” this is the basis of the cyclotron.
  • Galvanometer to ammeter: shunt S (small, parallel). To voltmeter: series R (large). Both use Ig = full-scale current of galvanometer.
  • Magnetic force does zero work โ€” this is a conceptual question that appears every few years. Force is perpendicular to velocity โ†’ W = 0 โ†’ speed constant.
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