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Modern Physics

Photoelectric effect, atomic spectra, radioactivity, and nuclear physics β€” the chapter where quantum meets the exam. Expect 3–4 EAPCET questions.

3–4Questions in EAPCET
~3%Paper Weightage
10Core Formulas
4Mistake Traps

Concept Core

Planck's quanta, photoelectric effect, atomic spectra, radioactivity β€” the quantum revolution.

Photoelectric Effect β€” Einstein's Equation

Light incident on a metal surface ejects electrons if frequency Ξ½ β‰₯ threshold frequency Ξ½β‚€:

E = hΞ½ = KE_max + Ο† = hΞ½β‚€ + KE_max KE_max = hΞ½ βˆ’ Ο† = h(Ξ½ βˆ’ Ξ½β‚€) = eVβ‚€

Ο† = work function (energy to eject an electron). Vβ‚€ = stopping potential. h = 6.626Γ—10⁻³⁴ JΒ·s.

Key facts: KE_max is independent of intensity. Stopping potential Vβ‚€ = KE_max/e. Rate of emission ∝ intensity (number of photons).

Photon Properties
Energy: E = hΞ½ = hc/Ξ» Momentum: p = h/Ξ» = E/c Rest mass: 0 (always moves at c) de Broglie (matter wave): Ξ» = h/p = h/mv

Photons travel at c always. No rest mass. Their "mass-equivalent" from E = mcΒ² gives effective inertia for momentum purposes.

Bohr's Atomic Model (Recap)
Eβ‚™ = βˆ’13.6/nΒ² eV (H atom) rβ‚™ = 0.529nΒ² Γ… Number of spectral lines from orbit n: n(nβˆ’1)/2

Energy levels are negative (bound state). Ionisation energy = |E₁| = 13.6 eV. Emission spectrum: electron falls to lower orbit.

Radioactivity β€” Decay Laws
N = Nβ‚€ e^(βˆ’Ξ»t) = Nβ‚€ (1/2)^(t/t₁/β‚‚) Activity A = Ξ»N = Aβ‚€ e^(βˆ’Ξ»t) t₁/β‚‚ = 0.693/Ξ» = ln2/Ξ» Mean life Ο„ = 1/Ξ» = t₁/β‚‚/0.693

Ξ» = decay constant. Activity in Becquerel (1 Bq = 1 decay/s) or Curie (1 Ci = 3.7Γ—10¹⁰ Bq).

Nuclear Reactions β€” Mass Defect & Binding Energy
Mass defect: Ξ”m = Zm_p + (Aβˆ’Z)m_n βˆ’ M_nucleus Binding energy: BE = Ξ”m Γ— cΒ² = Ξ”m Γ— 931.5 MeV/u BE per nucleon = BE/A

Higher BE/nucleon β†’ more stable nucleus. Iron (Fe-56) is most stable. Fission (heavy nuclei split) and fusion (light nuclei merge) both release energy by moving toward Fe-56.

Alpha, Beta, Gamma Decay
DecayEmissionEffect on (Z,A)
Ξ± decayβ‚‚He⁴Zβˆ’2, Aβˆ’4
β⁻ decayelectron + antineutrinoZ+1, A unchanged
β⁺ decaypositron + neutrinoZβˆ’1, A unchanged
Ξ³ decayphotonNo change in Z, A

Formula Vault

Modern physics formulas β€” photoelectric, photon, radioactivity, and nuclear.

Einstein's Photoelectric
KE_max = hΞ½ βˆ’ Ο† = eVβ‚€
Ο† = work function; Vβ‚€ = stopping potential
Threshold Frequency
Ξ½β‚€ = Ο†/h
hΞ½β‚€ = Ο†; minimum frequency
Photon Energy
E = hΞ½ = hc/Ξ»
h = 6.626Γ—10⁻³⁴ JΒ·s
Photon Momentum
p = h/Ξ» = E/c
Zero rest mass, p β‰  0
de Broglie
Ξ» = h/mv = h/p
All matter has wavelength
Radioactive Decay
N = Nβ‚€ e^(βˆ’Ξ»t)
Ξ» = decay constant
Half-Life
t₁/β‚‚ = 0.693/Ξ»
After n half-lives: N = Nβ‚€(Β½)ⁿ
Activity
A = Ξ»N (Becquerel)
1 Ci = 3.7Γ—10¹⁰ Bq
Binding Energy
BE = Ξ”m Γ— 931.5 MeV/u
Ξ”m in atomic mass units (u)
Q-value of Reaction
Q = (m_reactants βˆ’ m_products)cΒ²
Q > 0: exothermic; Q < 0: endothermic

Worked Examples

5 problems β€” photoelectric, half-life, mass-energy, nuclear decay, and a trap.

EasyFind KE of photoelectrons: Ξ½=1.5Γ—10¹⁡ Hz, Ο†=3.0 eVβ–Ύ
Light of frequency 1.5Γ—10¹⁡ Hz strikes a metal with work function 3.0 eV. Find max KE. (h=4.14Γ—10⁻¹⁡ eVΒ·s)
1
E = hΞ½ = 4.14Γ—10⁻¹⁡ Γ— 1.5Γ—10¹⁡ = 6.21 eV
2
KE_max = hΞ½ βˆ’ Ο† = 6.21 βˆ’ 3.0 = 3.21 eV
βœ“  KE_max = 3.21 eV
EasyAfter 3 half-lives, what fraction of a radioactive sample remains?β–Ύ
A radioactive sample has half-life 2 years. What fraction remains after 6 years?
1
n = 6/2 = 3 half-lives
2
N/Nβ‚€ = (1/2)Β³ = 1/8
βœ“  Fraction remaining = 1/8
MediumAlpha decay of Ra-226: write the daughter nucleusβ–Ύ
Radium-226 (β‚ˆβ‚ˆRa²²⁢) undergoes Ξ± decay. Write the daughter nucleus.
1
Ξ± particle is β‚‚He⁴. Conservation: A: 226βˆ’4=222, Z: 88βˆ’2=86
2
Element with Z=86 is Radon (Rn)
3
β‚ˆβ‚ˆRa²²⁢ β†’ β‚‚He⁴ + β‚ˆβ‚†RnΒ²Β²Β²
βœ“  Daughter nucleus: β‚ˆβ‚†RnΒ²Β²Β² (Radon-222)
EAPCET LevelFind binding energy per nucleon for He-4 (Ξ”m=0.0304 u)β–Ύ
Calculate the binding energy per nucleon of He-4 if the mass defect Ξ”m = 0.0304 u.
1
BE = Ξ”m Γ— 931.5 MeV/u = 0.0304 Γ— 931.5 = 28.32 MeV
2
A = 4 nucleons
3
BE per nucleon = 28.32/4 = 7.08 MeV/nucleon
βœ“  BE per nucleon = 7.08 MeV/nucleon
Trap QuestionIncreasing light intensity increases the kinetic energy of photoelectrons β€” True or False?β–Ύ
A student claims: 'Brighter light gives photoelectrons more energy.' Evaluate.
1
The trap: Einstein's photoelectric equation: KE_max = hΞ½ βˆ’ Ο†. Only Ξ½ (frequency) appears β€” not intensity.
2
Increasing intensity increases the NUMBER of photons, not their individual energy.
3
More photons β†’ more electrons ejected (larger photoelectric current).
4
But each photon has the same energy hΞ½ β€” so KE_max of each electron is unchanged.
βœ“  False β€” intensity affects rate of emission (current), not KE. Only frequency (Ξ½) determines KE_max

Mistake DNA

4 modern physics errors that cost marks in EAPCET.

πŸ’‘
Intensity Affects Kinetic Energy in Photoelectric Effect
In the photoelectric effect, KE_max depends only on frequency. Intensity controls the NUMBER of photoelectrons emitted per second.
❌ Wrong
Brighter light β†’ higher KE_max βœ— (Einstein's equation has no intensity term)
βœ“ Correct
KE_max = hΞ½ βˆ’ Ο† βœ“ Intensity β†’ more electrons βœ“ (larger current, same KE_max)
Einstein: each photon has energy hΞ½. Higher intensity = more photons = more electrons ejected, but each electron still gets the same energy from each photon.
βš›οΈ
β⁻ Decay Changes Mass Number A
In β⁻ decay, a neutron converts to a proton. Z increases by 1 but A stays the same (total nucleons unchanged).
❌ Wrong
β⁻ decay: ¹⁴₆C β†’ ¹⁰₅B + e⁻ βœ— (A changed from 14 to 10!)
βœ“ Correct
β⁻ decay: Z+1, A same βœ“ ¹⁴₆C β†’ ¹⁴₇N + e⁻ + Ξ½Μ„ βœ“ Neutron β†’ proton + electron
β⁻: n β†’ p + e⁻ + antineutrino. Proton count Z increases by 1. Neutron count decreases by 1. Total A = Z + N is unchanged.
πŸ”’
Half-Life vs Mean Life Confusion
t₁/β‚‚ β‰  Ο„ (mean life). Mean life Ο„ = t₁/β‚‚/0.693 = 1/Ξ». Mean life is longer than half-life.
❌ Wrong
Mean life = half-life βœ— Ο„ = t₁/β‚‚ βœ—
βœ“ Correct
Ο„ = 1/Ξ» = t₁/β‚‚/0.693 βœ“ Ο„ = 1.44 Γ— t₁/β‚‚ βœ“ Mean life > half-life
After one half-life, N = Nβ‚€/2. After one mean life Ο„, N = Nβ‚€/e β‰ˆ 0.368Nβ‚€. Half-life is when 50% remains; mean life (longer) is when 36.8% remains.
🌊
de Broglie: Wavelength Depends Only on Speed (Forgetting Mass)
Ξ» = h/mv. Both mass AND velocity matter. A heavier particle moving at the same speed has a shorter wavelength.
❌ Wrong
Same speed v: proton Ξ» = electron Ξ» βœ— (different masses!)
βœ“ Correct
Ξ» = h/mv βœ“ Proton (1836Γ— heavier) has 1836Γ— shorter Ξ» for same speed βœ“
de Broglie wavelength Ξ» = h/mv = h/p. Larger momentum β†’ smaller wavelength. This is why macroscopic objects have negligibly small de Broglie wavelengths.

Chapter Intelligence

Modern Physics connects quantum concepts to atomic structure and nuclear energy.

EAPCET Weightage (2019–2024)
Photoelectric effect
~8
Radioactive decay and half-life
~7
Bohr's atomic model / spectra
~6
Nuclear reactions (Ξ±,Ξ²,Ξ³)
~5
Binding energy / mass defect
~4
de Broglie wavelength
~3
High-Yield PYQ Patterns
KE_max = hΞ½ βˆ’ Ο† calculationN remaining after n half-livesΞ±/Ξ² decay β€” find daughter nucleusBinding energy per nucleonStopping potential from frequencyde Broglie wavelength of particleActivity from decay constant
Exam Strategy
  • Photoelectric: KE_max = hΞ½ βˆ’ Ο† = eVβ‚€. Frequency determines KE; intensity determines current. This conceptual distinction is tested every year.
  • Radioactivity: N = Nβ‚€(Β½)ⁿ where n = t/t₁/β‚‚. Count half-lives elapsed first, then apply.
  • Nuclear decay: Ξ± removes 4 from A, 2 from Z. β⁻ changes Z+1 but A stays same. Ξ³ changes neither A nor Z.
  • Binding energy: BE = Ξ”m Γ— 931.5 MeV/u. Higher BE/nucleon = more stable. Fe-56 is most stable.
  • This chapter connects to Atomic Structure (Bohr model, spectra) and to EMI/waves (wave-particle duality).
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